#include<bits/stdc++.h>
using namespace std;

int tab[2][13] = {
    {0, 31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31},
    {0, 31, 29, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31},
};

bool LeapYear(int year){
	return ( (!(year%4) && year%100) || !(year%400) );
}

//计算这两个日期分别与0000.00.00的日期差值再作差
int ManyDays(int year, int month, int day){
	int sum = 0;
	for(int i=0; i<year; i++){
		for(int j=1; j<13; j++)
			sum += tab[LeapYear(i)][j];
	}
	for(int i=1; i<month; i++)
		sum += tab[LeapYear(year)][i];
	sum += day;
	return sum;
}

int main(){
	int year1, month1, day1;
	int year2, month2, day2;
	while(~scanf("%4d%2d%2d",&year1, &month1, &day1)){
		scanf("%4d%2d%2d",&year2, &month2, &day2);
		int sum1 = ManyDays(year1, month1,day1);
		int sum2 = ManyDays(year2, month2,day2);
		printf("%d\n", abs(sum1-sum2)+1);//此处注意两个连续日期规定其间天数为2
	}
	return 0;
}