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这个题它怎么就跟我过不去呢啊啊啊啊啊啊啊啊啊啊啊啊啊啊啊啊啊啊啊
#include<stdio.h>
int main()
{
char c[1000] = { '\0' };
char m[26] = {"abcdefghijklmnopqrstuvwxyz"};
int i,j,n;
int count[26] = {0};
scanf("%d", &n);
for (i = 0; i <= n; i++)
scanf("%c", &c[i]);
for (j = 0; j < 26; j++)
{
for (i = 0; i <= n; i++)
{
if (c[i] == m[j])
count[j]++;
}
if ((count[j] != 0) && (count[j] % 5 == 0 || count[j] % 7 == 0))
printf("%c %d\n", m[j]...
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不能写成char m[26] = {"abcdefghijklmnopqrstuvwxyz"};这样吧，改成下面这样：
char m[26] = {'a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z'};
char类型是一个字符一个字符的存的。