#include <stdio.h> main( ) { int a[ ]={1, 2, 3, 4, 5, 6}; int x, y, *p; p = &a[0]; x = *(p+2); y = *(p+4); printf(“*p=%d, x=%d, y=%d\n”, *p, x, y); }
运行结果为：
1 3 5
*p=1,x=3,y=5
*p=1, x=3, y=5
*p=1 x=3, y=5
p=1,x=3,y=5
*p=1, x=3,y=5
*p=1， x=3， y=5
*p=1,x=4,y=6
1，3，5
p=1, x=3, y=5
zzw1803472614 回复 zzw1803472614： *p=1, x=3, y=5
*p=0, x=3, y=5
*P=1，x=3，y=5
1,3,5
135
*p = 1 x = 3 y = 5
用户登录可进行刷题及查看答案
The road of your choice, you have to go on !
粤ICP备16082171号-1
登录后提交答案